This is only a preview of the January 2003 issue of Silicon Chip. You can view 20 of the 96 pages in the full issue, including the advertisments. For full access, purchase the issue for $10.00 or subscribe for access to the latest issues. Articles in this series:
Items relevant to "Reader/Programmer For Smart Cards":
Items relevant to "The SC480 50W RMS Amplifier Module":
Items relevant to "A Tiptronic-Style Gear Indicator":
Items relevant to "Active 3-Way Crossover For Loudspeaker Systems":
Items relevant to "Using Linux To Share An Optus Cable Modem: Pt.3":
Articles in this series:
Purchase a printed copy of this issue for $10.00. |
Notes & Errata
40W Fluorescent Inverter, September 2002: Mosfets Q1 & Q2
have been found to be prone to
overheating when the PC board
is placed within the confines of
a slimline 36W fluorescent tube
batten. To correct this, the inverter
has been altered to improve efficiency without reducing the lamp
brightness.
Changes include reducing the
334V DC supply to 280V and winding transformer T1 differently.
The voltage change requires replacing one of the 270kΩ resistors
leading to pin 1 of IC1 with a 180kΩ
resistor. The changes to T1 involve
using 130 turns on the secondary.
For the primary use figure-8 7.5A
wire with a polarity stripe. Insert
one end of the figure-8 wire in the S1
& F1 holes nearest to Q2 and wind
on five turns, starting up through the
centre of the core and anticlockwise
towards S2 & F2. Insert the wire
ends into S2 & F2 with continuity
(same wire) between S1 and S2 and
the second wire between F1 and F2.
This means that if the polarity stripe
on the figure-8 wire is at S1, it then
terminates into S2.
rating of more the than load current
being switched. This should suppress
any contact arcing across the relay
contacts.
When switching 240VAC with
a solenoid, it is usual to connect a
250VAC-rated capacitor across the (solenoid) contacts. Try a 47nF (.047µF)
250VAC capacitor across the contacts.
High input impedance
amplifier wanted
I would like a suggestion for a high
input impedance ampli
fier circuit.
What I need is to be able to intercept
a line level signal and basically split
it in to two line level signals. I need it
high impedance so that it doesn’t load
the line too much.
I want to build five of these amplifiers and then use them to provide
line-level outputs from each channel
of my Boston Acoustics BA7500G
Speaker system so I can feed external
amps, without disturbing the internal
92 Silicon Chip
Set the current drain from the
battery at 3A (300mV across the
0.1W resistor used in the current
measurement set-up in Fig.8).
As noted in December 2002, it is
recommended that the maximum
current delivered to the fluorescent
tube be adjusted using a trimpot.
The 100kΩ resistor connecting between pin 2 of IC3 and the top of
the dimming potentiometer (VR1)
should be replaced with a 50kΩ
trimpot and series 82kΩ resistor.
The 1.2Ω resistor between the
source of Q4 and ground should be
changed to 2.2Ω to allow the full
dimming range available from VR1.
Using the current measuring
setup of Fig.8, the trimpot should
be adjusted for the 300mV, corresponding to 3A when the dimming
pot (VR1) is turned fully clockwise.
Note that this adjustment should
be made after the inverter has been
running for some time and is fully
warmed up. Once adjusted, the
trimpot and 82kΩ resistor can be
swapped for a single resistor that
is the same value as the total series
combination.
When testing the current (using
amplifier. Any help would be greatly
appreciated. (M. R., via email).
• You really don’t need a high input
impedance. What you need is a buffer
amplifier that can drive a series of low
impedance outputs. We have already
published a suitable circuit – the audio
portion of the Audio/Video Distribution Amplifier in November 2001.
This circuit is based on an LM833
dual op amp.
If you decide to use it, make sure
you install 1kΩ resistors in the outputs instead of the 47kΩ resistors
mistakenly specified in the original
article.
Speed control in
cordless drills
I recently bought a variable speed
cordless drill/screw
d river (Black
& Decker) and would like to know
what method is used to provide the
variable speed feature. I guess I could
open the drill and look inside but
the setup of Fig.8), it is important
not to have the 0.1Ω 5W resistor
in series with the supply for any
appreciable length of time as the
current drain will begin to increase.
To prevent this, short out the 0.1Ω
resistor (with a clip lead) when not
making the measurement. Remove
the clip lead briefly to make the
current measurement.
In addition, use heavy gauge wire
rated at 7.5A or more to connect the
inverter to the 12V battery.
It is recommended that the inverter not be used while the battery is
being charged from a high current
charger such as an automotive
alternator or mains-powered unit.
If the inverter Mosfets still run
excessively hot, it is recommended
to reduce the current drain to 2.5A
(250mV across the 0.1Ω resistor)
which will reduce the lamp brightness slightly.
With slimline batten holders,
ventilation can be improved by
drilling some holes in the side of
the batten adjacent to the Q1 and
Q2 heatsinks and some extra holes
at the other end of the batten to
SC
allow air flow.
that will void my warranty. (H. P., via
email).
• Cordless drills are usually permanent magnet motors with a Mosfet
switchmode power control, usually
running at about 1kHz or so. In fact,
you can usually hear the 1kHz tone at
very low speed settings.
Temperature
controlled fan
I want a circuit for a temperature-controlled fan for the heatsinks
of an amplifier I’m working on. I am
positive SILICON CHIP published one
in the not-too-distant past but for the
life of me I can’t find it in my back
issues, nor can I locate it on your
website. Can you recall where the circuit appeared please? (G. B., Scotland
Island, NSW).
• The circuit was associated with
the Ultra-LD Amplifier in the August
2000 issue. There were two options: a
SC
thermistor or thermal cutout.
www.siliconchip.com.au
|