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. . . continued from page 102
different types and even between individual LEDs in a batch. We can’t
see any problems with what you are
suggesting. The 220kΩ resistor gives
LED2 a little under 1mA. The design
assumes it has a fairly high efficiency
to give sufficient brightness with so litsiliconchip.com.au
tle current, which is true of many red
LEDs but perhaps not yours.
There are two limits on how low a
resistor value you can use: the LED’s
current rating and the resistor’s power
rating. The LED current rating would
not be exceeded unless the resistor
value was less than 22kΩ so that is
unlikely to be a problem.
The resistor dissipation is going to
be roughly 265V2 ÷ R. That’s 320mW
for the specified 220kΩ resistor, which
has a rating of 1W. So you could reduce
the value to as low as 100kΩ, resulting in a dissipation of around 700mW.
That would more than double the LED
current and should increase the brightness sufficiently.
You can use 180kΩ or the parallel
1MΩ resistor if you only need a slight
increase in brightness. If you use the
parallel resistor approach, make sure
May 2016 103
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