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I found the issue. Values for R1 are
provided for the currents of 200mA,
400mA and 500mA, 600mA.
According to the data sheet for the
LM317T, the formula for working out
the current for R1 is I = Vref ÷ R. So for
example, working it out for 200mA, for
the given value of R1 = 1.2W, I = 1.25
÷ 1.2 gives 1.041A and not 200mA.
Shouldn't it be 6.2W, ie, I = 1.25 ÷ 6.2
gives 0.201A or 201mA? Please correct
me if I am wrong. (R. M., Perth, WA)
• The current limit is set by transistor
Q1 and not the LM317T. So as current
flows through Rcl, there is a voltage
siliconchip.com.au
produced across this resistor. When
Rcl is 1.2W and with 200mA current,
there will be a voltage drop of 0.6V
across the resistor and so the transistor base voltage will be 0.6V above
the emitter. The transistor will conduct, pulling the adjust pin of REG1
low. This has the effect of reducing
the output voltage of REG1 to limit
current to 200mA.
The calculation of the current limit
you provide for the LM317 is when the
output is connected to the adjust pin
via a resistor and current is drawn at
the adjust pin. However, in the Float
Charger circuit, the arrangement is
different and the output of REG1 is
set by resistor R2 in series with R1,
between the output and adjust terminals. Overall output voltage above the
adjust pin is set by the current through
R3 and VR1.
Resistor R1 in this circuit is only
required to protect against a short
circuit at the output. In the event of a
short circuit, Q1 will switch on fully
but this can only reduce the output
voltage to around 1.25V.
This voltage then appears across
R1 which dissipates the excess
May 2017 111
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